years_diff

Returns the year difference between two date expressions (expr1 − expr2), accurate to the year.

Syntax

Haskell

BIGINT years_diff(DATETIME expr1,DATETIME expr2);

Parameters

expr1: the end time. It must be of the DATETIME or DATE type.
expr2: the start time. It must be of the DATETIME or DATE type.

Return value

Returns a BIGINT value.

NULL is returned if the date does not exist, for example, 2022-02-29.

Examples

Plain

select years_diff('2010-11-30 23:59:59', '2000-11-1 23:59:59');
+---------------------------------------------------------+
| years_diff('2010-11-30 23:59:59', '2000-11-1 23:59:59') |
+---------------------------------------------------------+
|                                                      10 |
+---------------------------------------------------------+

select years_diff('2010-11-30', '2000-11-1');
+---------------------------------------+
| years_diff('2010-11-30', '2000-11-1') |
+---------------------------------------+
|                                    10 |
+---------------------------------------+