crates/ty_python_semantic/resources/mdtest/overloads.md
Reference: https://typing.python.org/en/latest/spec/overload.html
typing.overloadThe definition of typing.overload in typeshed is an identity function.
from typing import overload
def foo(x: int) -> int:
return x
reveal_type(foo) # revealed: def foo(x: int) -> int
bar = overload(foo)
reveal_type(bar) # revealed: def foo(x: int) -> int
from typing import overload
@overload
def add() -> None: ...
@overload
def add(x: int) -> int: ...
@overload
def add(x: int, y: int) -> int: ...
def add(x: int | None = None, y: int | None = None) -> int | None:
return (x or 0) + (y or 0)
reveal_type(add) # revealed: Overload[() -> None, (x: int) -> int, (x: int, y: int) -> int]
reveal_type(add()) # revealed: None
reveal_type(add(1)) # revealed: int
reveal_type(add(1, 2)) # revealed: int
These scenarios are to verify that the overloaded and non-overloaded definitions are correctly overridden by each other.
An overloaded function is overriding another overloaded function:
from typing import overload
@overload
def foo() -> None: ...
@overload
def foo(x: int) -> int: ...
def foo(x: int | None = None) -> int | None:
return x
reveal_type(foo) # revealed: Overload[() -> None, (x: int) -> int]
reveal_type(foo()) # revealed: None
reveal_type(foo(1)) # revealed: int
@overload
def foo() -> None: ...
@overload
def foo(x: str) -> str: ...
def foo(x: str | None = None) -> str | None:
return x
reveal_type(foo) # revealed: Overload[() -> None, (x: str) -> str]
reveal_type(foo()) # revealed: None
reveal_type(foo("")) # revealed: str
A non-overloaded function is overriding an overloaded function:
def foo(x: int) -> int:
return x
reveal_type(foo) # revealed: def foo(x: int) -> int
An overloaded function is overriding a non-overloaded function:
reveal_type(foo) # revealed: def foo(x: int) -> int
@overload
def foo() -> None: ...
@overload
def foo(x: bytes) -> bytes: ...
def foo(x: bytes | None = None) -> bytes | None:
return x
reveal_type(foo) # revealed: Overload[() -> None, (x: bytes) -> bytes]
reveal_type(foo()) # revealed: None
reveal_type(foo(b"")) # revealed: bytes
from typing_extensions import Self, overload
class Foo1:
@overload
def method(self) -> None: ...
@overload
def method(self, x: int) -> int: ...
def method(self, x: int | None = None) -> int | None:
return x
foo1 = Foo1()
reveal_type(foo1.method) # revealed: Overload[() -> None, (x: int) -> int]
reveal_type(foo1.method()) # revealed: None
reveal_type(foo1.method(1)) # revealed: int
class Foo2:
@overload
def method(self) -> None: ...
@overload
def method(self, x: str) -> str: ...
def method(self, x: str | None = None) -> str | None:
return x
foo2 = Foo2()
reveal_type(foo2.method) # revealed: Overload[() -> None, (x: str) -> str]
reveal_type(foo2.method()) # revealed: None
reveal_type(foo2.method("")) # revealed: str
class Foo3:
@overload
def takes_self_or_int(self: Self, x: Self) -> Self: ...
@overload
def takes_self_or_int(self: Self, x: int) -> int: ...
def takes_self_or_int(self: Self, x: Self | int) -> Self | int:
return x
foo3 = Foo3()
reveal_type(foo3.takes_self_or_int(foo3)) # revealed: Foo3
reveal_type(foo3.takes_self_or_int(1)) # revealed: int
from typing import overload
class Foo:
@overload
def __init__(self) -> None: ...
@overload
def __init__(self, x: int) -> None: ...
def __init__(self, x: int | None = None) -> None:
self.x = x
foo = Foo()
reveal_type(foo) # revealed: Foo
reveal_type(foo.x) # revealed: int | None
foo1 = Foo(1)
reveal_type(foo1) # revealed: Foo
reveal_type(foo1.x) # revealed: int | None
Function definitions can vary between multiple Python versions.
Here, the same function is overloaded in one version and not in another.
[environment]
python-version = "3.9"
from __future__ import annotations
import sys
from typing import overload
if sys.version_info < (3, 10):
def func(x: int) -> int:
return x
elif sys.version_info <= (3, 12):
@overload
def func() -> None: ...
@overload
def func(x: int) -> int: ...
def func(x: int | None = None) -> int | None:
return x
reveal_type(func) # revealed: def func(x: int) -> int
func() # error: [missing-argument]
[environment]
python-version = "3.10"
import sys
from typing import overload
if sys.version_info < (3, 10):
def func(x: int) -> int:
return x
elif sys.version_info <= (3, 12):
@overload
def func() -> None: ...
@overload
def func(x: int) -> int: ...
def func(x: int | None = None) -> int | None:
return x
reveal_type(func) # revealed: Overload[() -> None, (x: int) -> int]
reveal_type(func()) # revealed: None
reveal_type(func(1)) # revealed: int
[environment]
python-version = "3.9"
overloaded.pyi:
import sys
from typing import overload
if sys.version_info >= (3, 10):
@overload
def func() -> None: ...
@overload
def func(x: int) -> int: ...
@overload
def func(x: str) -> str: ...
main.py:
from overloaded import func
reveal_type(func) # revealed: Overload[(x: int) -> int, (x: str) -> str]
func() # error: [no-matching-overload]
reveal_type(func(1)) # revealed: int
reveal_type(func("")) # revealed: str
[environment]
python-version = "3.10"
overloaded.pyi:
import sys
from typing import overload
@overload
def func() -> None: ...
if sys.version_info >= (3, 10):
@overload
def func(x: int) -> int: ...
@overload
def func(x: str) -> str: ...
main.py:
from overloaded import func
reveal_type(func) # revealed: Overload[() -> None, (x: int) -> int, (x: str) -> str]
reveal_type(func()) # revealed: None
reveal_type(func(1)) # revealed: int
reveal_type(func("")) # revealed: str
[environment]
python-version = "3.12"
For an overloaded generic function, it's not necessary for all overloads to be generic.
from typing import overload
@overload
def func() -> None: ...
@overload
def func[T](x: T) -> T: ...
def func[T](x: T | None = None) -> T | None:
return x
reveal_type(func) # revealed: Overload[() -> None, [T](x: T) -> T]
reveal_type(func()) # revealed: None
reveal_type(func(1)) # revealed: Literal[1]
reveal_type(func("")) # revealed: Literal[""]
At least two @overload-decorated definitions must be present.
from typing import overload
@overload
# error: [invalid-overload]
def func(x: int) -> int: ...
def func(x: int | str) -> int | str:
return x
from typing import overload
@overload
# error: [invalid-overload]
def func(x: int) -> int: ...
In regular modules, a series of @overload-decorated definitions must be followed by exactly one
non-@overload-decorated definition (for the same function/method).
from typing import overload
@overload
# error: [invalid-overload] "Overloads for function `func` must be followed by a non-`@overload`-decorated implementation function"
def func(x: int) -> int: ...
@overload
def func(x: str) -> str: ...
class Foo:
@overload
# error: [invalid-overload] "Overloads for function `method` must be followed by a non-`@overload`-decorated implementation function"
def method(self, x: int) -> int: ...
@overload
def method(self, x: str) -> str: ...
Overload definitions within stub files are exempt from this check.
from typing import overload
@overload
def func(x: int) -> int: ...
@overload
def func(x: str) -> str: ...
Overload definitions within protocols are exempt from this check.
from typing import Protocol, overload
class Foo(Protocol):
@overload
def f(self, x: int) -> int: ...
@overload
def f(self, x: str) -> str: ...
Overload definitions within abstract base classes are exempt from this check.
from abc import ABC, abstractmethod
from typing import overload
class AbstractFoo(ABC):
@overload
@abstractmethod
def f(self, x: int) -> int: ...
@overload
@abstractmethod
def f(self, x: str) -> str: ...
Using the @abstractmethod decorator requires that the class's metaclass is ABCMeta or is derived
from it.
from abc import ABCMeta
class CustomAbstractMetaclass(ABCMeta): ...
class Fine(metaclass=CustomAbstractMetaclass):
@overload
@abstractmethod
def f(self, x: int) -> int: ...
@overload
@abstractmethod
def f(self, x: str) -> str: ...
class Foo:
@overload
@abstractmethod
# error: [invalid-overload]
def f(self, x: int) -> int: ...
@overload
@abstractmethod
def f(self, x: str) -> str: ...
And, the @abstractmethod decorator must be present on all the @overload-ed methods.
class PartialFoo1(ABC):
@overload
@abstractmethod
# error: [invalid-overload]
def f(self, x: int) -> int: ...
@overload
def f(self, x: str) -> str: ...
class PartialFoo(ABC):
@overload
# error: [invalid-overload]
def f(self, x: int) -> int: ...
@overload
@abstractmethod
def f(self, x: str) -> str: ...
TYPE_CHECKING blocksAs in other areas of ty, we treat TYPE_CHECKING blocks the same as "inline stub files", so we
permit overloaded functions to exist without an implementation if all overloads are defined inside
an if TYPE_CHECKING block:
from typing import overload, TYPE_CHECKING
if TYPE_CHECKING:
@overload
def a() -> str: ...
@overload
def a(x: int) -> int: ...
class F:
@overload
def method(self) -> None: ...
@overload
def method(self, x: int) -> int: ...
class G:
if TYPE_CHECKING:
@overload
def method(self) -> None: ...
@overload
def method(self, x: int) -> int: ...
if TYPE_CHECKING:
@overload
def b() -> str: ...
if TYPE_CHECKING:
@overload
def b(x: int) -> int: ...
if TYPE_CHECKING:
import sys
if sys.platform == "win32":
pass
else:
@overload
def d() -> bytes: ...
@overload
def d(x: int) -> int: ...
if TYPE_CHECKING:
@overload
# not all overloads are in a `TYPE_CHECKING` block, so this is an error
def c() -> None: ... # error: [invalid-overload]
@overload
def c(x: int) -> int: ...
@overload-decorated functions with non-stub bodiesIf an @overload-decorated function has a non-trivial body, it likely indicates a misunderstanding
on the part of the user. We emit a warning-level diagnostic to alert them of this.
..., pass and docstrings are all fine:
from typing import overload
@overload
def x(y: int) -> int: ...
@overload
def x(y: str) -> str:
"""Docstring"""
@overload
def x(y: bytes) -> bytes:
pass
@overload
def x(y: memoryview) -> memoryview:
"""More docs"""
pass
...
def x(y):
return y
Anything else, however, will trigger the lint:
@overload
def foo(x: int) -> int:
return x # error: [useless-overload-body]
@overload
def foo(x: str) -> None:
"""Docstring"""
pass
print("oh no, a string") # error: [useless-overload-body]
def foo(x):
return x
@staticmethodIf one overload signature is decorated with @staticmethod, all overload signatures must be
similarly decorated. The implementation, if present, must also have a consistent decorator.
from __future__ import annotations
from typing import overload
class CheckStaticMethod:
@overload
def method1(x: int) -> int: ...
@overload
def method1(x: str) -> str: ...
@staticmethod
# error: [invalid-overload] "Overloaded function `method1` does not use the `@staticmethod` decorator consistently"
def method1(x: int | str) -> int | str:
return x
@overload
def method2(x: int) -> int: ...
@overload
@staticmethod
def method2(x: str) -> str: ...
@staticmethod
# error: [invalid-overload]
def method2(x: int | str) -> int | str:
return x
@overload
@staticmethod
def method3(x: int) -> int: ...
@overload
@staticmethod
def method3(x: str) -> str: ...
# error: [invalid-overload]
def method3(x: int | str) -> int | str:
return x
@overload
@staticmethod
def method4(x: int) -> int: ...
@overload
@staticmethod
def method4(x: str) -> str: ...
@staticmethod
def method4(x: int | str) -> int | str:
return x
@classmethodThe same rules apply for @classmethod as for @staticmethod.
from __future__ import annotations
from typing import overload
class CheckClassMethod:
def __init__(self, x: int) -> None:
self.x = x
@overload
@classmethod
def try_from1(cls, x: int) -> CheckClassMethod: ...
@overload
def try_from1(cls, x: str) -> None: ...
@classmethod
# error: [invalid-overload] "Overloaded function `try_from1` does not use the `@classmethod` decorator consistently"
def try_from1(cls, x: int | str) -> CheckClassMethod | None:
if isinstance(x, int):
return cls(x)
return None
@overload
def try_from2(cls, x: int) -> CheckClassMethod: ...
@overload
@classmethod
def try_from2(cls, x: str) -> None: ...
@classmethod
# error: [invalid-overload]
def try_from2(cls, x: int | str) -> CheckClassMethod | None:
if isinstance(x, int):
return cls(x)
return None
@overload
@classmethod
def try_from3(cls, x: int) -> CheckClassMethod: ...
@overload
@classmethod
def try_from3(cls, x: str) -> None: ...
# error: [invalid-overload]
def try_from3(cls, x: int | str) -> CheckClassMethod | None:
if isinstance(x, int):
# error: [call-non-callable]
return cls(x)
return None
@overload
@classmethod
def try_from4(cls, x: int) -> CheckClassMethod: ...
@overload
@classmethod
def try_from4(cls, x: str) -> None: ...
@classmethod
def try_from4(cls, x: int | str) -> CheckClassMethod | None:
if isinstance(x, int):
return cls(x)
return None
@finalIf a @final decorator is supplied for a function with overloads, the decorator should be applied
only to the overload implementation if it is present.
from typing_extensions import final, overload
class Foo:
@overload
def method1(self, x: int) -> int: ...
@overload
def method1(self, x: str) -> str: ...
@final
def method1(self, x: int | str) -> int | str:
return x
@overload
@final
# error: [invalid-overload]
def method2(self, x: int) -> int: ...
@overload
def method2(self, x: str) -> str: ...
def method2(self, x: int | str) -> int | str:
return x
@overload
def method3(self, x: int) -> int: ...
@overload
@final
# error: [invalid-overload]
def method3(self, x: str) -> str: ...
def method3(self, x: int | str) -> int | str:
return x
If an overload implementation isn't present (for example, in a stub file), the @final decorator
should be applied only to the first overload.
from typing_extensions import final, overload
class Foo:
@overload
@final
def method1(self, x: int) -> int: ...
@overload
def method1(self, x: str) -> str: ...
@overload
def method2(self, x: int) -> int: ...
@final
@overload
# error: [invalid-overload]
def method2(self, x: str) -> str: ...
@overload
def method3(self, x: int) -> int: ...
@final
@overload
def method3(self, x: str) -> int: ... # error: [invalid-overload]
@overload
@final
def method3(self, x: bytes) -> bytes: ... # error: [invalid-overload]
@overload
def method3(self, x: bytearray) -> bytearray: ...
@overrideThe same rules apply for @override as for @final.
from typing_extensions import overload, override
class Base:
@overload
def method(self, x: int) -> int: ...
@overload
def method(self, x: str) -> str: ...
def method(self, x: int | str) -> int | str:
return x
class Sub1(Base):
@overload
def method(self, x: int) -> int: ...
@overload
def method(self, x: str) -> str: ...
@override
def method(self, x: int | str) -> int | str:
return x
class Sub2(Base):
@overload
def method(self, x: int) -> int: ...
@overload
@override
# error: [invalid-overload]
def method(self, x: str) -> str: ...
def method(self, x: int | str) -> int | str:
return x
class Sub3(Base):
@overload
@override
# error: [invalid-overload]
def method(self, x: int) -> int: ...
@overload
def method(self, x: str) -> str: ...
def method(self, x: int | str) -> int | str:
return x
And, similarly, in stub files:
from typing_extensions import overload, override
class Base:
@overload
def method(self, x: int) -> int: ...
@overload
def method(self, x: str) -> str: ...
class Sub1(Base):
@overload
@override
def method(self, x: int) -> int: ...
@overload
def method(self, x: str) -> str: ...
class Sub2(Base):
@overload
def method(self, x: int) -> int: ...
@overload
@override
# error: [invalid-overload]
def method(self, x: str) -> str: ...
def statement shadows a non-def symbol with the same nameWe used to panic on snippets like these (see https://github.com/astral-sh/ty/issues/1867), because
"iterating over the overloads" for the def statement would incorrectly list the overloads of the
imported function.
module.pyi:
from typing import overload
@overload
def f() -> int: ...
@overload
def f(x) -> str: ...
@overload
def g() -> int: ...
@overload
def g(x) -> str: ...
main.py:
import module
foo = module.f
# revealed: Overload[() -> int, (x) -> str]
reveal_type(foo)
def foo(): ...
# revealed: def foo() -> Unknown
reveal_type(foo)
bar = module.g
# revealed: Overload[() -> int, (x) -> str]
reveal_type(bar)
@staticmethod
def bar(): ...
# revealed: def bar() -> Unknown
reveal_type(bar)
def statement shadows a non-def symbol with the same name, defined in the same scopeThis is an even more pathological version of the above test. This version used to fail in the same
way as the above snippet, but would only fail in a stub file, or in a .py file that had an
overloaded function without an implementation. (Note that this is not always invalid even in .py
files: we allow overloaded functions to omit the implementation function if they are decorated with
@abstractmethod or they are defined in if TYPE_CHECKING blocks.)
from typing import overload
@overload
def h() -> int: ...
@overload
def h(x) -> str: ...
baz = h
# revealed: Overload[() -> int, (x) -> str]
reveal_type(baz)
# This function is distinct from `h`, despite `h` originating
# from the same scope and being aliased to the same name
# in the same scope!
@overload
def baz(x, y) -> bytes: ...
@overload
def baz(x, y, z) -> list[str]: ...
def baz(x, y, z=None) -> bytes | list[str]:
return b""
# revealed: Overload[(x, y) -> bytes, (x, y, z) -> list[str]]
reveal_type(baz)