staticMethod.inVoidCast

Code example

<?php declare(strict_types = 1);

class Logger
{
	public static function log(string $message): bool
	{
		return file_put_contents('log.txt', $message) !== false;
	}
}

(void) Logger::log('Hello');

Why is it reported?

The static method call is wrapped in a (void) cast, but the method does not require its return value to be used. The (void) cast is meant for explicitly discarding the return value of methods marked with #[\NoDiscard] to suppress the staticMethod.resultDiscarded error. When a method already allows its return value to be discarded, using (void) is unnecessary.

How to fix it

Remove the (void) cast and call the method directly:

 <?php declare(strict_types = 1);

-(void) Logger::log('Hello');
+Logger::log('Hello');

If the return value is needed, assign it to a variable:

 <?php declare(strict_types = 1);

-(void) Logger::log('Hello');
+$success = Logger::log('Hello');