return.void

Code example

<?php declare(strict_types = 1);

function doFoo(): void
{
	return 'hello';
}

Why is it reported?

A function or method with a void return type declaration attempts to return a value. In PHP, functions declared with void must not return any value. A bare return; statement is allowed, but return $value; is not.

This is a violation of PHP's type system and will cause a fatal error at runtime in strict mode.

How to fix it

Either remove the returned value:

 function doFoo(): void
 {
-	return 'hello';
+	// perform side effects only
 }

Or change the return type to match the returned value:

-function doFoo(): void
+function doFoo(): string
 {
 	return 'hello';
 }