generator.outOfFunction

Code example

<?php declare(strict_types = 1);

yield 1;
yield from doFoo();

Why is it reported?

The yield and yield from expressions can only be used inside a function or method body. Using them at the top level of a script or in a non-function context is not valid PHP. Generators require a function scope because PHP needs to create a Generator object from the function's execution context.

How to fix it

Wrap the yield expression inside a function or method:

-yield 1;
-yield from doFoo();
+function generateValues(): \Generator
+{
+	yield 1;
+	yield from doFoo();
+}