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enum.nameInUse

website/errors/enum.nameInUse.md

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Original Source

Code example

php
<?php declare(strict_types = 1);

namespace App;

use App\Enums\Status;

enum Status: string
{
	case Active = 'active';
	case Inactive = 'inactive';
}

Why is it reported?

An enum is being declared with a name that is already in use within the same namespace. This happens when a use statement imports a type with the same short name as the enum being declared. PHP cannot resolve which Status is intended, resulting in a fatal error at runtime.

In the example above, Status is imported via use App\Enums\Status and then an enum named Status is declared in the App namespace, creating a name conflict.

How to fix it

Rename the enum to avoid the conflict:

diff-php
 <?php declare(strict_types = 1);

 namespace App;

 use App\Enums\Status;

-enum Status: string
+enum UserStatus: string
 {
 	case Active = 'active';
 	case Inactive = 'inactive';
 }

Or use an alias for the imported type:

diff-php
 <?php declare(strict_types = 1);

 namespace App;

-use App\Enums\Status;
+use App\Enums\Status as BaseStatus;

 enum Status: string
 {
 	case Active = 'active';
 	case Inactive = 'inactive';
 }

Or remove the use statement if the imported type is not needed:

diff-php
 <?php declare(strict_types = 1);

 namespace App;

-use App\Enums\Status;
-
 enum Status: string
 {
 	case Active = 'active';
 	case Inactive = 'inactive';
 }