website/errors/enum.nameInUse.md
<?php declare(strict_types = 1);
namespace App;
use App\Enums\Status;
enum Status: string
{
case Active = 'active';
case Inactive = 'inactive';
}
An enum is being declared with a name that is already in use within the same namespace. This happens when a use statement imports a type with the same short name as the enum being declared. PHP cannot resolve which Status is intended, resulting in a fatal error at runtime.
In the example above, Status is imported via use App\Enums\Status and then an enum named Status is declared in the App namespace, creating a name conflict.
Rename the enum to avoid the conflict:
<?php declare(strict_types = 1);
namespace App;
use App\Enums\Status;
-enum Status: string
+enum UserStatus: string
{
case Active = 'active';
case Inactive = 'inactive';
}
Or use an alias for the imported type:
<?php declare(strict_types = 1);
namespace App;
-use App\Enums\Status;
+use App\Enums\Status as BaseStatus;
enum Status: string
{
case Active = 'active';
case Inactive = 'inactive';
}
Or remove the use statement if the imported type is not needed:
<?php declare(strict_types = 1);
namespace App;
-use App\Enums\Status;
-
enum Status: string
{
case Active = 'active';
case Inactive = 'inactive';
}