continue.outOfLoop

Code example

<?php declare(strict_types = 1);

class Foo
{
	public function doFoo(): void
	{
		if (rand(0, 1)) {
			continue;
		}
	}
}

Why is it reported?

The continue keyword can only be used inside a loop (for, foreach, while, do-while) or a switch statement. Using continue outside of these structures is a fatal error in PHP because there is no enclosing loop to continue to the next iteration of.

This also applies when continue appears inside a closure that is nested within a loop -- the closure creates a new scope, so continue inside it does not refer to the outer loop.

How to fix it

Use return instead if the intent is to exit the function:

 <?php declare(strict_types = 1);

 class Foo
 {
 	public function doFoo(): void
 	{
 		if (rand(0, 1)) {
-			continue;
+			return;
 		}
 	}
 }

Or move the code inside a loop if a loop was intended:

 <?php declare(strict_types = 1);

 class Foo
 {
 	public function doFoo(): void
 	{
+		while (true) {
 			if (rand(0, 1)) {
 				continue;
 			}
+		}
 	}
 }