argument.vsprintf

Code example

<?php declare(strict_types = 1);

$result = vsprintf('%s is %d years old and lives in %s', ['Alice', 30]);

Why is it reported?

The number of format placeholders in the vsprintf format string does not match the number of values in the array argument. The vsprintf function requires the array to contain exactly as many values as there are placeholders in the format string. A mismatch will result in missing values or ignored extra values at runtime.

In the example above, the format string '%s is %d years old and lives in %s' contains 3 placeholders, but the array only provides 2 values.

How to fix it

Pass the correct number of values in the array to match the placeholders:

 <?php declare(strict_types = 1);

-$result = vsprintf('%s is %d years old and lives in %s', ['Alice', 30]);
+$result = vsprintf('%s is %d years old and lives in %s', ['Alice', 30, 'London']);

Or adjust the format string if fewer values are intended:

 <?php declare(strict_types = 1);

-$result = vsprintf('%s is %d years old and lives in %s', ['Alice', 30]);
+$result = vsprintf('%s is %d years old', ['Alice', 30]);