argument.sprintf

Code example

<?php declare(strict_types = 1);

$name = 'world';
$result = sprintf('%s is %d years old and lives in %s', $name, 25);

Why is it reported?

The number of format placeholders in the sprintf format string does not match the number of values passed. The sprintf function requires exactly as many value arguments as there are placeholders in the format string. A mismatch will result in missing values or ignored extra arguments at runtime.

In the example above, the format string '%s is %d years old and lives in %s' contains 3 placeholders (%s, %d, %s), but only 2 values ($name, 25) are provided.

How to fix it

Pass the correct number of arguments to match the placeholders:

 <?php declare(strict_types = 1);

 $name = 'world';
-$result = sprintf('%s is %d years old and lives in %s', $name, 25);
+$result = sprintf('%s is %d years old and lives in %s', $name, 25, 'London');

Or adjust the format string if fewer values are intended:

 <?php declare(strict_types = 1);

 $name = 'world';
-$result = sprintf('%s is %d years old and lives in %s', $name, 25);
+$result = sprintf('%s is %d years old', $name, 25);