vendors/fftw3/doc/html/FFTW-Execution-in-Fortran.html
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In C, in order to use a plan, one normally calls fftw_execute, which executes the plan to perform the transform on the input/output arrays passed when the plan was created (see Using Plans). The corresponding subroutine call in legacy Fortran is:
call dfftw_execute(plan)
However, we have had reports that this causes problems with some recent optimizing Fortran compilers. The problem is, because the input/output arrays are not passed as explicit arguments to dfftw_execute, the semantics of Fortran (unlike C) allow the compiler to assume that the input/output arrays are not changed by dfftw_execute. As a consequence, certain compilers end up optimizing out or repositioning the call to dfftw_execute, assuming incorrectly that it does nothing.
There are various workarounds to this, but the safest and simplest thing is to not use dfftw_execute in Fortran. Instead, use the functions described in New-array Execute Functions, which take the input/output arrays as explicit arguments. For example, if the plan is for a complex-data DFT and was created for the arrays in and out, you would do:
call dfftw_execute_dft(plan, in, out)
There are a few things to be careful of, however:
dfftw_execute_dft, Real-input (r2c) DFT plans should use use dfftw_execute_dft_r2c, and real-output (c2r) DFT plans should use dfftw_execute_dft_c2r. The various r2r plans should use dfftw_execute_r2r.fftw_malloc in C). You can, of course, use the FFTW_UNALIGNED flag when creating the plan, in which case the plan does not depend on the alignment, but this may sacrifice substantial performance on architectures (like x86) with SIMD instructions (see SIMD alignment and fftw_malloc).Next: Fortran Examples, Previous: FFTW Constants in Fortran, Up: Calling FFTW from Legacy Fortran [Contents][Index]