examples/notebook/graph/simple_min_cost_flow_program.ipynb
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First, you must install ortools package in this colab.
%pip install ortools
From Bradley, Hax and Maganti, 'Applied Mathematical Programming', figure 8.1.
import numpy as np
from ortools.graph.python import min_cost_flow
def main():
"""MinCostFlow simple interface example."""
# Instantiate a SimpleMinCostFlow solver.
smcf = min_cost_flow.SimpleMinCostFlow()
# Define four parallel arrays: sources, destinations, capacities,
# and unit costs between each pair. For instance, the arc from node 0
# to node 1 has a capacity of 15.
start_nodes = np.array([0, 0, 1, 1, 1, 2, 2, 3, 4])
end_nodes = np.array([1, 2, 2, 3, 4, 3, 4, 4, 2])
capacities = np.array([15, 8, 20, 4, 10, 15, 4, 20, 5])
unit_costs = np.array([4, 4, 2, 2, 6, 1, 3, 2, 3])
# Define an array of supplies at each node.
supplies = [20, 0, 0, -5, -15]
# Add arcs, capacities and costs in bulk using numpy.
all_arcs = smcf.add_arcs_with_capacity_and_unit_cost(
start_nodes, end_nodes, capacities, unit_costs
)
# Add supply for each nodes.
smcf.set_nodes_supplies(np.arange(0, len(supplies)), supplies)
# Find the min cost flow.
status = smcf.solve()
if status != smcf.OPTIMAL:
print("There was an issue with the min cost flow input.")
print(f"Status: {status}")
exit(1)
print(f"Minimum cost: {smcf.optimal_cost()}")
print("")
print(" Arc Flow / Capacity Cost")
solution_flows = smcf.flows(all_arcs)
costs = solution_flows * unit_costs
for arc, flow, cost in zip(all_arcs, solution_flows, costs):
print(
f"{smcf.tail(arc):1} -> "
f"{smcf.head(arc)} {flow:3} / {smcf.capacity(arc):3} {cost}"
)
main()