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coins3

examples/notebook/contrib/coins3.ipynb

2016-063.3 KB
Original Source
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http://www.apache.org/licenses/LICENSE-2.0

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coins3

<table align="left"> <td> <a href="https://colab.research.google.com/github/google/or-tools/blob/main/examples/notebook/contrib/coins3.ipynb">Run in Google Colab</a> </td> <td> <a href="https://github.com/google/or-tools/blob/main/examples/contrib/coins3.py">View source on GitHub</a> </td> </table>

First, you must install ortools package in this colab.

python
%pip install ortools

Coin application in Google CP Solver.

From 'Constraint Logic Programming using ECLiPSe' pages 99f and 234 ff. The solution in ECLiPSe is at page 236.

''' What is the minimum number of coins that allows one to pay exactly any amount smaller than one Euro? Recall that there are six different euro cents, of denomination 1, 2, 5, 10, 20, 50 '''

Compare with the following models:

This model was created by Hakan Kjellerstrand ([email protected]) Also see my other Google CP Solver models: http://www.hakank.org/google_or_tools/

python
import sys
from ortools.constraint_solver import pywrapcp


def main():
  # Create the solver.
  solver = pywrapcp.Solver("Coins")

  #
  # data
  #
  n = 6  # number of different coins
  variables = [1, 2, 5, 10, 25, 50]

  # declare variables
  x = [solver.IntVar(0, 99, "x%i" % i) for i in range(n)]
  num_coins = solver.IntVar(0, 99, "num_coins")

  #
  # constraints
  #

  # number of used coins, to be minimized
  solver.Add(num_coins == solver.Sum(x))

  # Check that all changes from 1 to 99 can be made.
  for j in range(1, 100):
    tmp = [solver.IntVar(0, 99, "b%i" % i) for i in range(n)]
    solver.Add(solver.ScalProd(tmp, variables) == j)
    [solver.Add(tmp[i] <= x[i]) for i in range(n)]

  # objective
  objective = solver.Minimize(num_coins, 1)

  #
  # solution and search
  #
  solution = solver.Assignment()
  solution.Add(x)
  solution.Add(num_coins)
  solution.AddObjective(num_coins)

  db = solver.Phase(x, solver.CHOOSE_MIN_SIZE_LOWEST_MAX,
                    solver.ASSIGN_MIN_VALUE)

  solver.NewSearch(db, [objective])
  num_solutions = 0
  while solver.NextSolution():
    print("x: ", [x[i].Value() for i in range(n)])
    print("num_coins:", num_coins.Value())
    print()
    num_solutions += 1
  solver.EndSearch()

  print()
  print("num_solutions:", num_solutions)
  print("failures:", solver.Failures())
  print("branches:", solver.Branches())
  print("WallTime:", solver.WallTime())


main()