website/content.en/ChapterFour/1800~1899/1877.Minimize-Maximum-Pair-Sum-in-Array.md
The pair sum of a pair (a,b) is equal to a + b. The maximum pair sum is the largest pair sum in a list of pairs.
(1,5), (2,3), and (4,4), the maximum pair sum would be max(1+5, 2+3, 4+4) = max(6, 5, 8) = 8.Given an array nums of even length n, pair up the elements of nums into n / 2 pairs such that:
nums is in exactly one pair, andReturn the minimized maximum pair sum after optimally pairing up the elements.
Example 1:
Input: nums = [3,5,2,3]
Output: 7
Explanation: The elements can be paired up into pairs (3,3) and (5,2).
The maximum pair sum is max(3+3, 5+2) = max(6, 7) = 7.
Example 2:
Input: nums = [3,5,4,2,4,6]
Output: 8
Explanation: The elements can be paired up into pairs (3,5), (4,4), and (6,2).
The maximum pair sum is max(3+5, 4+4, 6+2) = max(8, 8, 8) = 8.
Constraints:
n == nums.length2 <= n <= 105n is even.1 <= nums[i] <= 105The pair sum of a pair (a,b) is equal to a + b. The maximum pair sum is the largest pair sum in an array of pairs.
Given an array nums of even length n, please divide the elements in nums into n / 2 pairs such that:
Return the minimized maximum pair sum under the optimal pairing scheme.
package leetcode
import "sort"
func minPairSum(nums []int) int {
sort.Ints(nums)
n, res := len(nums), 0
for i, val := range nums[:n/2] {
res = max(res, val+nums[n-1-i])
}
return res
}
func max(a, b int) int {
if a > b {
return a
}
return b
}