website/content.en/ChapterFour/0300~0399/0354.Russian-Doll-Envelopes.md
You have a number of envelopes with widths and heights given as a pair of integers (w, h). One envelope can fit into another if and only if both the width and height of one envelope is greater than the width and height of the other envelope.
What is the maximum number of envelopes can you Russian doll? (put one inside other)
Note: Rotation is not allowed.
Example:
Input: [[5,4],[6,4],[6,7],[2,3]]
Output: 3
Explanation: The maximum number of envelopes you can Russian doll is 3 ([2,3] => [5,4] => [6,7]).
Given some envelopes marked with widths and heights, where the width and height are given as integer pairs (w, h). When another envelope's width and height are both larger than this envelope's, this envelope can be put into the other envelope, like a Russian doll.
Please calculate the maximum number of envelopes that can form a set of “Russian doll” envelopes (that is, one envelope can be placed inside another).
Note:
package leetcode
import (
"sort"
)
type sortEnvelopes [][]int
func (s sortEnvelopes) Len() int {
return len(s)
}
func (s sortEnvelopes) Less(i, j int) bool {
if s[i][0] == s[j][0] {
return s[i][1] > s[j][1]
}
return s[i][0] < s[j][0]
}
func (s sortEnvelopes) Swap(i, j int) {
s[i], s[j] = s[j], s[i]
}
func maxEnvelopes(envelopes [][]int) int {
sort.Sort(sortEnvelopes(envelopes))
dp := []int{}
for _, e := range envelopes {
low, high := 0, len(dp)
for low < high {
mid := low + (high-low)>>1
if dp[mid] >= e[1] {
high = mid
} else {
low = mid + 1
}
}
if low == len(dp) {
dp = append(dp, e[1])
} else {
dp[low] = e[1]
}
}
return len(dp)
}