website/content/ChapterFour/1000~1099/1017.Convert-to-Base-2.md
Given a number N, return a string consisting of "0"s and "1"s that represents its value in base -2 (negative two).
The returned string must have no leading zeroes, unless the string is "0".
Example 1:
Input: 2
Output: "110"
Explantion: (-2) ^ 2 + (-2) ^ 1 = 2
Example 2:
Input: 3
Output: "111"
Explantion: (-2) ^ 2 + (-2) ^ 1 + (-2) ^ 0 = 3
Example 3:
Input: 4
Output: "100"
Explantion: (-2) ^ 2 = 4
Note:
0 <= N <= 10^9给出数字 N,返回由若干 "0" 和 "1"组成的字符串,该字符串为 N 的负二进制(base -2)表示。除非字符串就是 "0",否则返回的字符串中不能含有前导零。
提示:
package leetcode
import "strconv"
func baseNeg2(N int) string {
if N == 0 {
return "0"
}
res := ""
for N != 0 {
remainder := N % (-2)
N = N / (-2)
if remainder < 0 {
remainder += 2
N++
}
res = strconv.Itoa(remainder) + res
}
return res
}