leetcode/1710.Maximum-Units-on-a-Truck/README.md
You are assigned to put some amount of boxes onto one truck. You are given a 2D array boxTypes, where boxTypes[i] = [numberOfBoxesi, numberOfUnitsPerBoxi]:
numberOfBoxesi is the number of boxes of type i.numberOfUnitsPerBoxiis the number of units in each box of the type i.You are also given an integer truckSize, which is the maximum number of boxes that can be put on the truck. You can choose any boxes to put on the truck as long as the number of boxes does not exceed truckSize.
Return the maximum total number of units that can be put on the truck.
Example 1:
Input: boxTypes = [[1,3],[2,2],[3,1]], truckSize = 4
Output: 8
Explanation: There are:
- 1 box of the first type that contains 3 units.
- 2 boxes of the second type that contain 2 units each.
- 3 boxes of the third type that contain 1 unit each.
You can take all the boxes of the first and second types, and one box of the third type.
The total number of units will be = (1 * 3) + (2 * 2) + (1 * 1) = 8.
Example 2:
Input: boxTypes = [[5,10],[2,5],[4,7],[3,9]], truckSize = 10
Output: 91
Constraints:
1 <= boxTypes.length <= 10001 <= numberOfBoxesi, numberOfUnitsPerBoxi <= 10001 <= truckSize <= 106请你将一些箱子装在 一辆卡车 上。给你一个二维数组 boxTypes ,其中 boxTypes[i] = [numberOfBoxesi, numberOfUnitsPerBoxi] :
整数 truckSize 表示卡车上可以装载 箱子 的 最大数量 。只要箱子数量不超过 truckSize ,你就可以选择任意箱子装到卡车上。返回卡车可以装载 单元 的 最大 总数。
package leetcode
import "sort"
func maximumUnits(boxTypes [][]int, truckSize int) int {
sort.Slice(boxTypes, func(i, j int) bool {
return boxTypes[i][1] > boxTypes[j][1]
})
res := 0
for i := 0; truckSize > 0 && i < len(boxTypes); i++ {
if truckSize >= boxTypes[i][0] {
truckSize -= boxTypes[i][0]
res += (boxTypes[i][1] * boxTypes[i][0])
} else {
res += (truckSize * boxTypes[i][1])
truckSize = 0
}
}
return res
}