curriculum/challenges/english/blocks/rosetta-code-challenges/5a23c84252665b21eecc8028.md
For this task, the Stern-Brocot sequence is to be generated by an algorithm similar to that employed in generating the <a href="https://rosettacode.org/wiki/Fibonacci_sequence" target="_blank" rel="noopener noreferrer nofollow">Fibonacci sequence</a>.
<ol> <li>The first and second members of the sequence are both 1:</li> <ul><li>1, 1</li></ul> <li>Start by considering the second member of the sequence</li> <li>Sum the considered member of the sequence and its precedent, (1 + 1) = 2, and append it to the end of the sequence:</li> <ul><li>1, 1, 2</li></ul> <li>Append the considered member of the sequence to the end of the sequence:</li> <ul><li>1, 1, 2, 1</li></ul> <li>Consider the next member of the series, (the third member i.e. 2)</li> <li>GOTO 3 </li> <ul> <li></li> <li> ─── Expanding another loop we get: ───</li> <li></li> </ul> <li>Sum the considered member of the sequence and its precedent, (2 + 1) = 3, and append it to the end of the sequence:</li> <ul><li>1, 1, 2, 1, 3</li></ul> <li>Append the considered member of the sequence to the end of the sequence:</li> <ul><li>1, 1, 2, 1, 3, 2</li></ul> <li>Consider the next member of the series, (the fourth member i.e. 1)</li> </ol>Create a function that returns the position in the Stern-Brocot sequence at which $ n $ is first encountered, where the sequence is generated with the method outlined above. Note that this sequence uses 1 based indexing.
sternBrocot should be a function.
assert(typeof sternBrocot == 'function');
sternBrocot(2) should return a number.
assert(typeof sternBrocot(2) == 'number');
sternBrocot(2) should return 3.
assert.equal(sternBrocot(2), 3);
sternBrocot(3) should return 5.
assert.equal(sternBrocot(3), 5);
sternBrocot(5) should return 11.
assert.equal(sternBrocot(5), 11);
sternBrocot(7) should return 19.
assert.equal(sternBrocot(7), 19);
sternBrocot(10) should return 39.
assert.equal(sternBrocot(10), 39);
function sternBrocot(num) {
}
function sternBrocot(num) {
function f(n) {
return n < 2
? n
: n & 1
? f(Math.floor(n / 2)) + f(Math.floor(n / 2 + 1))
: f(Math.floor(n / 2));
}
function gcd(a, b) {
return a ? (a < b ? gcd(b % a, a) : gcd(a % b, b)) : b;
}
var n;
for (n = 1; f(n) != num; n++);
return n;
}