curriculum/challenges/english/blocks/rosetta-code-challenges/594810f028c0303b75339acf.md
The Ackermann function is a classic example of a recursive function, notable especially because it is not a primitive recursive function. It grows very quickly in value, as does the size of its call tree.
The Ackermann function is usually defined as follows:
$A(m, n) = \begin{cases} n+1 & \mbox{if } m = 0 \\ A(m-1, 1) & \mbox{if } m > 0 \mbox{ and } n = 0 \\ A(m-1, A(m, n-1)) & \mbox{if } m > 0 \mbox{ and } n > 0. \end{cases}$
Its arguments are never negative and it always terminates.
Write a function which returns the value of $A(m, n)$. Arbitrary precision is preferred (since the function grows so quickly), but not required.
ack should be a function.
assert(typeof ack === 'function');
ack(0, 0) should return 1.
assert(ack(0, 0) === 1);
ack(1, 1) should return 3.
assert(ack(1, 1) === 3);
ack(2, 5) should return 13.
assert(ack(2, 5) === 13);
ack(3, 3) should return 61.
assert(ack(3, 3) === 61);
function ack(m, n) {
}
function ack(m, n) {
return m === 0 ? n + 1 : ack(m - 1, n === 0 ? 1 : ack(m, n - 1));
}