--description--

The hyperexponentiation or tetration of a number $a$ by a positive integer $b$, denoted by $a↑↑b$ or ${}^ba$, is recursively defined by:

$a↑↑1 = a$,

$a↑↑(k+1) = a^{(a↑↑k)}$.

Thus we have e.g. $3↑↑2 = 3^3 = 27$, hence $3↑↑3 = 3^{27} = 7625597484987$ and $3↑↑4$ is roughly ${10}^{3.6383346400240996 \times {10}^{12}}$. Find the last 8 digits of $1777↑↑1855$.

--hints--

hyperexponentation() should return 95962097.

assert.strictEqual(hyperexponentation(), 95962097);

--seed--

--seed-contents--

function hyperexponentation() {

  return true;
}

hyperexponentation();

--solutions--

// solution required