--description--

Let $N$ be a positive integer and let $N$ be split into $k$ equal parts, $r = \frac{N}{k}$, so that $N = r + r + \cdots + r$.

Let $P$ be the product of these parts, $P = r × r × \cdots × r = r^k$.

For example, if 11 is split into five equal parts, 11 = 2.2 + 2.2 + 2.2 + 2.2 + 2.2, then $P = {2.2}^5 = 51.53632$.

Let $M(N) = P_{max}$ for a given value of $N$.

It turns out that the maximum for $N = 11$ is found by splitting eleven into four equal parts which leads to $P_{max} = {(\frac{11}{4})}^4$; that is, $M(11) = \frac{14641}{256} = 57.19140625$, which is a terminating decimal.

However, for $N = 8$ the maximum is achieved by splitting it into three equal parts, so $M(8) = \frac{512}{27}$, which is a non-terminating decimal.

Let $D(N) = N$ if $M(N)$ is a non-terminating decimal and $D(N) = -N$ if $M(N)$ is a terminating decimal.

For example, $\sum D(N)$ for $5 ≤ N ≤ 100$ is 2438.

Find $\sum D(N)$ for $5 ≤ N ≤ 10000$.

--hints--

maximumProductOfParts() should return 48861552.

assert.strictEqual(maximumProductOfParts(), 48861552);

--seed--

--seed-contents--

function maximumProductOfParts() {

  return true;
}

maximumProductOfParts();

--solutions--

// solution required