Back to Freecodecamp

Problem 73: Counting fractions in a range

curriculum/challenges/english/blocks/project-euler-problems-1-to-100/5900f3b61000cf542c50fec8.md

latest2.9 KB
Original Source

--description--

Consider the fraction, $\frac{n}{d}$, where n and d are positive integers. If n < d and highest common factor, ${HCF}(n, d) = 1$, it is called a reduced proper fraction.

If we list the set of reduced proper fractions for d ≤ 8 in ascending order of size, we get:

$$\frac{1}{8}, \frac{1}{7}, \frac{1}{6}, \frac{1}{5}, \frac{1}{4}, \frac{2}{7}, \frac{1}{3}, \mathbf{\frac{3}{8}, \frac{2}{5}, \frac{3}{7}}, \frac{1}{2}, \frac{4}{7}, \frac{3}{5}, \frac{5}{8}, \frac{2}{3}, \frac{5}{7}, \frac{3}{4}, \frac{4}{5}, \frac{5}{6}, \frac{6}{7}, \frac{7}{8}$$

It can be seen that there are 3 fractions between $\frac{1}{3}$ and $\frac{1}{2}$.

How many fractions lie between $\frac{1}{3}$ and $\frac{1}{2}$ in the sorted set of reduced proper fractions for dlimit?

--hints--

countingFractionsInARange(8) should return a number.

js
assert(typeof countingFractionsInARange(8) === 'number');

countingFractionsInARange(8) should return 3.

js
assert.strictEqual(countingFractionsInARange(8), 3);

countingFractionsInARange(1000) should return 50695.

js
assert.strictEqual(countingFractionsInARange(1000), 50695);

countingFractionsInARange(6000) should return 1823861.

js
assert.strictEqual(countingFractionsInARange(6000), 1823861);

countingFractionsInARange(12000) should return 7295372.

js
assert.strictEqual(countingFractionsInARange(12000), 7295372);

--seed--

--seed-contents--

js
function countingFractionsInARange(limit) {

  return true;
}

countingFractionsInARange(8);

--solutions--

js
class PrimeSeive {
  constructor(num) {
    const seive = Array(Math.floor((num - 1) / 2)).fill(true);
    const upper = Math.floor((num - 1) / 2);
    const sqrtUpper = Math.floor((Math.sqrt(num) - 1) / 2);

    for (let i = 0; i <= sqrtUpper; i++) {
      if (seive[i]) {
        // Mark value in seive array
        const prime = 2 * i + 3;
        // Mark all multiples of this number as false (not prime)
        const primeSquaredIndex = 2 * i ** 2 + 6 * i + 3;
        for (let j = primeSquaredIndex; j < upper; j += prime) {
          seive[j] = false;
        }
      }
    }

    this._seive = seive;
  }

  isPrime(num) {
    return num === 2
      ? true
      : num % 2 === 0
        ? false
        : this.isOddPrime(num);
  }

  isOddPrime(num) {
    return this._seive[(num - 3) / 2];
  }
};
const primeSeive = new PrimeSeive(12001);

function countingFractionsInARange(num) {
  const moebius = Array(num + 1).fill(1)

  // Generate Moebis function terms
  for (let i = 2; i <= num; i++) {
    if (!primeSeive.isPrime(i)) continue;
    for (let j = i; j <= num; j += i) moebius[j] *= -1;
    for (let j = i * i; j <= num; j += i * i) moebius[j] = 0;
  }
  // Evaluate totient sum
  let sum = 0;
  for (let i = 1; i <= num; i++) {
    const coeff = Math.floor(num / i - 2);
    sum += moebius[i] * Math.floor(coeff * coeff / 12 + 0.5);
  }
  return sum;
}