curriculum/challenges/english/blocks/learn-interfaces-by-building-an-equation-solver/667a7ce2a9925416e7b4781b.md
The structural pattern matching enables you to verify that the subject has a specific structure. In addition to that, it binds names in the pattern to elements of the subject. For example:
match my_list:
case [a]:
print(a)
case [a, b]:
print(a, b)
Modify your match/case construct to match results instead of len(results). Then, modify each case to use a list with the appropriate number of elements. Use x for the case the list contains a single element, and x1 and x2 for the case the list contains two elements.
Finally, modify the f-strings to use the variable names used in each case.
You should modify your match statement to use results as the subject value.
({ test: () => assert(runPython(`_Node(_code).find_function("solver").find_matches()[0].find_match_subject().is_equivalent("results")`)) })
You should modify your first case to use the pattern [].
({ test: () => assert(runPython(`_Node(_code).find_function("solver").find_matches()[0].find_match_cases()[0].find_case_pattern().is_equivalent("[]")`)) })
You should not modify your first case body.
({ test: () => assert(runPython(`_Node(_code).find_function("solver").find_matches()[0].find_match_cases()[0].find_body().is_equivalent("result_list = ['No real roots']")`)) })
You should modify your second case to use the pattern [x].
({ test: () => assert(runPython(`_Node(_code).find_function("solver").find_matches()[0].find_match_cases()[1].find_case_pattern().is_equivalent("[x]")`)) })
You should modify the f-string contained inside result_list to use x in place of result[0].
({ test: () => assert(runPython(`_Node(_code).find_function("solver").find_matches()[0].find_match_cases()[1].find_body().is_equivalent("result_list = [f'x = {x:+.3f}']")`)) })
You should modify your third case to use a list containing x1 and x2 as the pattern.
({ test: () => assert(runPython(`_Node(_code).find_function("solver").find_matches()[0].find_match_cases()[2].find_case_pattern().is_equivalent("[x1, x2]")`)) })
You should modify the f-strings contained inside result_list to use the bound variables from your pattern.
({ test: () => assert(runPython(`_Node(_code).find_function("solver").find_matches()[0].find_match_cases()[2].find_body().is_equivalent("result_list = [f'x1 = {x1:+.3f}', f'x2 = {x2:+.3f}']")`)) })
from abc import ABC, abstractmethod
import re
class Equation(ABC):
degree: int
type: str
def __init__(self, *args):
if (self.degree + 1) != len(args):
raise TypeError(
f"'Equation' object takes {self.degree + 1} positional arguments but {len(args)} were given"
)
if any(not isinstance(arg, (int, float)) for arg in args):
raise TypeError("Coefficients must be of type 'int' or 'float'")
if args[0] == 0:
raise ValueError("Highest degree coefficient must be different from zero")
self.coefficients = {(len(args) - n - 1): arg for n, arg in enumerate(args)}
def __init_subclass__(cls):
if not hasattr(cls, "degree"):
raise AttributeError(
f"Cannot create '{cls.__name__}' class: missing required attribute 'degree'"
)
if not hasattr(cls, "type"):
raise AttributeError(
f"Cannot create '{cls.__name__}' class: missing required attribute 'type'"
)
def __str__(self):
terms = []
for n, coefficient in self.coefficients.items():
if not coefficient:
continue
if n == 0:
terms.append(f'{coefficient:+}')
elif n == 1:
terms.append(f'{coefficient:+}x')
else:
terms.append(f"{coefficient:+}x**{n}")
equation_string = ' '.join(terms) + ' = 0'
return re.sub(r"(?<!\d)1(?=x)", "", equation_string.strip("+"))
@abstractmethod
def solve(self):
pass
@abstractmethod
def analyze(self):
pass
class LinearEquation(Equation):
degree = 1
type = 'Linear Equation'
def solve(self):
a, b = self.coefficients.values()
x = -b / a
return [x]
def analyze(self):
slope, intercept = self.coefficients.values()
return {'slope': slope, 'intercept': intercept}
class QuadraticEquation(Equation):
degree = 2
type = 'Quadratic Equation'
def __init__(self, *args):
super().__init__(*args)
a, b, c = self.coefficients.values()
self.delta = b**2 - 4 * a * c
def solve(self):
if self.delta < 0:
return []
a, b, _ = self.coefficients.values()
x1 = (-b + (self.delta) ** 0.5) / (2 * a)
x2 = (-b - (self.delta) ** 0.5) / (2 * a)
if self.delta == 0:
return [x1]
return [x1, x2]
def analyze(self):
a, b, c = self.coefficients.values()
x = -b / (2 * a)
y = a * x**2 + b * x + c
if a > 0:
concavity = 'upwards'
min_max = 'min'
else:
concavity = 'downwards'
min_max = 'max'
return {'x': x, 'y': y, 'min_max': min_max, 'concavity': concavity}
def solver(equation):
if not isinstance(equation, Equation):
raise TypeError("Argument must be an Equation object")
output_string = f'\n{equation.type:-^24}'
output_string += f'\n\n{equation!s:^24}\n\n'
output_string += f'{"Solutions":-^24}\n\n'
results = equation.solve()
--fcc-editable-region--
match len(results):
case 0:
result_list = ['No real roots']
case 1:
result_list = [f'x = {results[0]:+.3f}']
case 2:
result_list = [f'x1 = {results[0]:+.3f}', f'x2 = {results[1]:+.3f}']
--fcc-editable-region--
for result in result_list:
output_string += f'{result:^24}\n'
return output_string
lin_eq = LinearEquation(2, 3)
quadr_eq = QuadraticEquation(1, 2, 1)
print(solver(lin_eq))