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Challenge 169: FizzBuzz Mini

curriculum/challenges/english/blocks/daily-coding-challenges-python/696655d24b614176d4c9b78c.md

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--description--

Given an integer, return a string based on the following rules:

  • If the number is divisible by 3, return "Fizz".
  • If the number is divisible by 5, return "Buzz".
  • If the number is divisible by both 3 and 5, return "FizzBuzz".
  • Otherwise, return the given number as a string.

--hints--

fizz_buzz_mini(3) should return "Fizz".

js
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(fizz_buzz_mini(3), "Fizz")`)
}})

fizz_buzz_mini(4) should return "4".

js
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(fizz_buzz_mini(4), "4")`)
}})

fizz_buzz_mini(35) should return "Buzz".

js
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(fizz_buzz_mini(35), "Buzz")`)
}})

fizz_buzz_mini(75) should return "FizzBuzz".

js
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(fizz_buzz_mini(75), "FizzBuzz")`)
}})

fizz_buzz_mini(98) should return "98".

js
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(fizz_buzz_mini(98), "98")`)
}})

--seed--

--seed-contents--

py
def fizz_buzz_mini(n):

    return n

--solutions--

py
def fizz_buzz_mini(n):
    if n % 3 == 0 and n % 5 == 0:
        return "FizzBuzz"
    if n % 3 == 0:
        return "Fizz"
    if n % 5 == 0:
        return "Buzz"
    return str(n)