curriculum/challenges/english/blocks/daily-coding-challenges-python/69162d64f96574d9bb629f02.md
Given two arrays, return a new array containing the symmetric difference of them.
difference([1, 2, 3], [3, 4, 5]) should return [1, 2, 4, 5].
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(difference([1, 2, 3], [3, 4, 5]), [1, 2, 4, 5])`)
}})
difference(["a", "b"], ["c", "b"]) should return ["a", "c"].
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(difference(["a", "b"], ["c", "b"]), ["a", "c"])`)
}})
difference([1, "a", 2], [2, "b", "a"]) should return [1, "b"].
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(difference([1, "a", 2], [2, "b", "a"]), [1, "b"])`)
}})
difference([1, 3, 5, 7, 9], [1, 2, 3, 4, 5, 6, 7, 8, 9]) should return [2, 4, 6, 8].
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(difference([1, 3, 5, 7, 9], [1, 2, 3, 4, 5, 6, 7, 8, 9]), [2, 4, 6, 8])`)
}})
def difference(arr1, arr2):
return arr1
def difference(arr1, arr2):
diff = []
for v in arr1:
if v not in arr2 and v not in diff:
diff.append(v)
for v in arr2:
if v not in arr1 and v not in diff:
diff.append(v)
return diff