curriculum/challenges/english/blocks/daily-coding-challenges-python/68ffb91507a5b645769328ca.md
Given an integer (n), return an array of integers from 1 to n (inclusive), replacing numbers that are multiple of:
"Fizz"."Buzz"."FizzBuzz".fizz_buzz(2) should return [1, 2].
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(fizz_buzz(2), [1, 2])`)
}})
fizz_buzz(4) should return [1, 2, "Fizz", 4].
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(fizz_buzz(4), [1, 2, "Fizz", 4])`)
}})
fizz_buzz(8) should return [1, 2, "Fizz", 4, "Buzz", "Fizz", 7, 8].
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(fizz_buzz(8), [1, 2, "Fizz", 4, "Buzz", "Fizz", 7, 8])`)
}})
fizz_buzz(20) should return [1, 2, "Fizz", 4, "Buzz", "Fizz", 7, 8, "Fizz", "Buzz", 11, "Fizz", 13, 14, "FizzBuzz", 16, 17, "Fizz", 19, "Buzz"].
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(fizz_buzz(20), [1, 2, "Fizz", 4, "Buzz", "Fizz", 7, 8, "Fizz", "Buzz", 11, "Fizz", 13, 14, "FizzBuzz", 16, 17, "Fizz", 19, "Buzz"])`)
}})
fizz_buzz(50) should return [1, 2, "Fizz", 4, "Buzz", "Fizz", 7, 8, "Fizz", "Buzz", 11, "Fizz", 13, 14, "FizzBuzz", 16, 17, "Fizz", 19, "Buzz", "Fizz", 22, 23, "Fizz", "Buzz", 26, "Fizz", 28, 29, "FizzBuzz", 31, 32, "Fizz", 34, "Buzz", "Fizz", 37, 38, "Fizz", "Buzz", 41, "Fizz", 43, 44, "FizzBuzz", 46, 47, "Fizz", 49, "Buzz"].
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(fizz_buzz(50), [1, 2, "Fizz", 4, "Buzz", "Fizz", 7, 8, "Fizz", "Buzz", 11, "Fizz", 13, 14, "FizzBuzz", 16, 17, "Fizz", 19, "Buzz", "Fizz", 22, 23, "Fizz", "Buzz", 26, "Fizz", 28, 29, "FizzBuzz", 31, 32, "Fizz", 34, "Buzz", "Fizz", 37, 38, "Fizz", "Buzz", 41, "Fizz", 43, 44, "FizzBuzz", 46, 47, "Fizz", 49, "Buzz"])`)
}})
def fizz_buzz(n):
return n
def fizz_buzz(n):
result = []
for i in range(1, n+1):
if i % 15 == 0:
result.append("FizzBuzz")
elif i % 3 == 0:
result.append("Fizz")
elif i % 5 == 0:
result.append("Buzz")
else:
result.append(i)
return result