--description--

Given two strings, determine if they are anagrams of each other (contain the same characters in any order).

--hints--

are_anagrams("listen", "silent") should return true.

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertIs(are_anagrams("listen", "silent"), True)`)
}})

are_anagrams("School master", "The classroom") should return true.

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertIs(are_anagrams("School master", "The classroom"), True)`)
}})

are_anagrams("A gentleman", "Elegant man") should return true.

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertIs(are_anagrams("A gentleman", "Elegant man"), True)`)
}})

are_anagrams("Hello", "World") should return false.

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertIs(are_anagrams("Hello", "World"), False)`)
}})

are_anagrams("apple", "banana") should return false.

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertIs(are_anagrams("apple", "banana"), False)`)
}})

are_anagrams("cat", "dog") should return false.

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertIs(are_anagrams("cat", "dog"), False)`)
}})

def are_anagrams(str1, str2):

    return str1

def are_anagrams(str1, str2):
    def clean(s):
        return sorted(s.replace(" ", "").lower())
    
    return clean(str1) == clean(str2)