--description--

Given a timestamp (number of milliseconds since the Unix epoch), return:

• "odd" if the day of the month for that timestamp is odd.
• "even" if the day of the month for that timestamp is even.

For example, given 1769472000000, a timestamp for January 27th, 2026, return "odd" because the day number (27) is an odd number.

Note: The timestamp is in milliseconds and you should use the date in the UTC timezone, not in your local time.

--hints--

oddOrEvenDay(1769472000000) should return "odd".

assert.equal(oddOrEvenDay(1769472000000), "odd");

oddOrEvenDay(1769444440000) should return "even".

assert.equal(oddOrEvenDay(1769444440000), "even");

oddOrEvenDay(6739456780000) should return "odd".

assert.equal(oddOrEvenDay(6739456780000), "odd");

oddOrEvenDay(1) should return "odd".

assert.equal(oddOrEvenDay(1), "odd");

oddOrEvenDay(86400000) should return "even".

assert.equal(oddOrEvenDay(86400000), "even");

--seed--

--seed-contents--

function oddOrEvenDay(timestamp) {

  return timestamp;
}

--solutions--

function oddOrEvenDay(timestamp) {
  const date = new Date(timestamp);
  const day = date.getUTCDate();

  return day % 2 === 0 ? "even" : "odd";
}