TreeListView.GetNodeVisibleIndex(TreeListNode) Method

Returns the node’s position within a View among visible nodes.

Assembly : DevExpress.Xpf.Grid.v25.2.dll

NuGet Package : DevExpress.Wpf.Grid.Core

Declaration

csharp

public int GetNodeVisibleIndex(
    TreeListNode node
)

Public Function GetNodeVisibleIndex(
    node As TreeListNode
) As Integer

Name	Type	Description
node	TreeListNode

A TreeListNode object that is the node whose visible index is returned.

Type	Description
Int32

An integer value that specifies the node’s position among visible nodes. -1 if the specified node is hidden.

To obtain a node by its visible index, use the TreeListView.GetNodeByVisibleIndex method.

To learn more, see Obtaining Nodes.