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TreeListView.GetNodeByVisibleIndex(Int32) Method

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TreeListView.GetNodeByVisibleIndex(Int32) Method

Returns a node with the specified visible index.

Namespace : DevExpress.Xpf.Grid

Assembly : DevExpress.Xpf.Grid.v25.2.dll

NuGet Package : DevExpress.Wpf.Grid.Core

Declaration

csharp
public TreeListNode GetNodeByVisibleIndex(
    int visibleIndex
)
vb
Public Function GetNodeByVisibleIndex(
    visibleIndex As Integer
) As TreeListNode

Parameters

NameTypeDescription
visibleIndexInt32

An integer value that specifies the node’s position within a View.

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Returns

TypeDescription
TreeListNode

A TreeListNode object that is the node with the specified visible index. null ( Nothing in Visual Basic) if the node was not found.

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Remarks

To learn more, see Obtaining Nodes.

See Also

GetNodeByContent(Object)

GetNodeByCellValue(String, Object)

GetNodeByRowHandle(Int32)

TreeListView Class

TreeListView Members

DevExpress.Xpf.Grid Namespace